I have a hard time on this log question, can you explain it?
Given log(x)p = m and log(x)q = n find the following values in termm of m and n:
1) log(x)p^3q
2) log(x)P/q^2
the base are (x)
For the first one my attempt are
(log(x)m^3 )( log(x)n)
= nm^3
the second one i have no idea how to do it
thanks guys
Assuming that by log(x)p you mean ${\log_x}{p}$ and that by log(x)P/q^2 you mean ${\log_x}{p/q^2}$ then you would proceed as follows...
1) ${\log_x}{p^{3}{q}} = 3\log_x{p} + \log_xq = 3m + n$
2) $\log_x{p/{q^2}} = \log_x{p} - 2\log_x{q} = m - 2n$
Note that to simplify I used the rules...
1) $\log(ab) = \log{a}+\log{b}$ and
2) $\log{a^c} = c\log{a}$