Logarithmic equation (basic)

Question

I am stuck on how to solve this equation

My solution which I will post below is $10^{42}$

But the correct answer should be $42$.

$$7\log{x}-2\log{x^3}=42$$
$$7\log{x}-6\log{x}=42$$
$$\log{x}=42$$
$$x=10^{42}$$

Answer 1

That's fine, as an "alternative" to check

$$7\log{x}-2\log{x^3}=42\iff \frac73\log{x^3}-2\log{x^3}=\frac13\log x^3=42\iff \log x = 42$$

probably there is a typo in the book.