Is it possible to solve the following recursive relation?
$f(n) = \begin{cases} f(\frac{n}{\log{n}}) + 1 \quad n\geq 3 \\ 1 \qquad \qquad \quad \ \ n< 3 \end{cases}$
I tried to solve it by assuming $n = e^{m}$, but it didn't work.
Is it possible to solve the following recursive relation?
$f(n) = \begin{cases} f(\frac{n}{\log{n}}) + 1 \quad n\geq 3 \\ 1 \qquad \qquad \quad \ \ n< 3 \end{cases}$
I tried to solve it by assuming $n = e^{m}$, but it didn't work.
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