I m looking for a subgroup $H$ of the dihedral group $(D_{2019},\circ)$ so that:
With $(D_{2019},\circ)$ the group containing as elements
$b$: a reflexion on a symmetry axis, and
$a$: a rotation of $\frac{2\pi}{2019}$
On a “2019-gon”
- $H \neq D_{2019}$
- $H$ has an element with order $673$
- $a^{102} \circ b \in H \circ a$
What I have tried so far: out of the 3rd requirement I gathered: $a^{102}\circ b = a^{103}\circ b \circ a \in H \circ a$
So I thought that $H=\{1,a^3,a^6,…,ab,a^3b,…a^{2018}b\}$
But since $a^{103} \notin H$ This cannot be it. Where did I go wrong?
Any help would be very much appreciated, thank you
There's anti-commutativity in dihedral groups. Here $ab=ba^{-1}.$
So $$a^{102}ba^{-1}=a^{103}b.$$
So, take $H=\langle a^3,a^{103}b\rangle.$
Then $H=G$, because $a^{103}b\in G\setminus \langle a^3\rangle $.
Thus there's no way to.