$$\tan{\theta} = x$$ $\theta$ is in quadrant 2. Find values of the other 5 trig functions.
My confusion is about $x$ having to be negative because of the $-x$ value, even though it says "$x$".
$\sin{\theta} = \frac{x}{(x^2+1)^{\frac{1}{2}}}$
$\cos{\theta} = \frac{1}{(x^2+1)^{\frac{1}{2}}}$
$\tan{\theta} = x$
csc = (x^2+1)^.5/x
sec = (x^2+1)^.5
cot = 1/x