Math notation that I am not familiar with

Question

I am working on reverse engineering a game and have come across the following formula as a string in a config file:

A*(B^xt)+C; xt=A2*x*(T>x)*(B2^x+C2)

It would appear that I would solve for xt then plug it into the first function. However I don't know how to interpret the (T>x). I have static values for A, B, C, A2, B2, C2, T and they are as follows:

A: 300
B: 1.51
C: -319

A2: 1.8
B2: 0.93
C2: -0.64

T: 14

I know the outcomes of this equation to be:

x = 2, y = 365
x = 3, y = 714
x = 4, y = 1,241
x = 5, y = 2,036
(I can post more if needed)

My attempts to plug in the constants and x value (completely ignoring the (T>x)) have resulted in values that are not even close to what they are supposed to be. I'm hoping someone here can make sense of it, especially the (T>x) part. Thank you for any help you may be able to provide.

Answer 1

The values you've shown are consistent with y=A*(B^x)+C, if we interpret the caret ^ as exponentiation and round to the nearest integer:

300*(1.51^2)-319 =  365.03
300*(1.51^3)-319 =  713.885
300*(1.51^4)-319 = 1240.657
300*(1.51^5)-319 = 2036.082

So I'm not convinced that this code first computes xt and then plugs it into the first part; I'd suppose that the first part is computed first, using a previously established value of xt where it happens to be equal to x, and then, perhaps, the second part is used to change the value of xt to something mysterious.

Answer 2

The code (T > x) is used in some languages (e.g. MATLAB) as a boolean function, returning 1 when the condition is true, and 0 otherwise.

In other words, > is treated as a binary operator mapping $X\times Y$ to $\{0,1\}$.

For instance, if I had T = 4 and x = [0 1 2 3 4 5], then T > x would return [1 1 1 1 0].