I think that $\mathbb{Z}\times \mathbb{Z}_{2}$ isn't a cyclic group becuase we don't have any $(a,b)\in \mathbb{Z}\times \mathbb{Z}_{2}$ that can create the group $\mathbb{Z}\times \mathbb{Z}_{2}$.
I'm right?
Thank you!
I think that $\mathbb{Z}\times \mathbb{Z}_{2}$ isn't a cyclic group becuase we don't have any $(a,b)\in \mathbb{Z}\times \mathbb{Z}_{2}$ that can create the group $\mathbb{Z}\times \mathbb{Z}_{2}$.
I'm right?
Thank you!
In very short: suppose
$$\Bbb Z\times\Bbb Z_2=\langle\;(a,b)\;\rangle\;,\;\;a\in\Bbb Z\;,\;b\in\Bbb Z_2$$
Well, then how'd you solve $\;(a+1,b)=n(a,b)\;,\;\;n\in\Bbb Z\;?$