The Mathieu functions are the solutions for the equation
$$ y''+(a-2q\cos(2z))y=0 $$
If we require the solution has the form
$$ y(z) = e^{i r z}f(z) $$
where $f(z)$ is a periodic function with period of $2\pi$, then the parameter $a$ should satisfy Mathieu characteristic function
$$ a=\text{MatheiuCharacteristicA}(r,q) $$
My question is what's the condition of $a$ should satisfy, if the solution can be written as
$$ y(z)=e^{irz}f(z) $$
where $f(z)$ is a periodic function with period 1, i.e., $f(z+1)=f(z)$?
Update
It seems that the period of the original Mathieu function should be $\pi$ instead of $2\pi$, according to Wikipedia, MathWorld, and DLMF, and the documentation of Mathematica may be incorrect on that. That means the ordinary scaling of the equation works fine.
I recommend you to use Scilab Mathieu Functions Toolbox, not Mathematica.
The parameter a (or b) is a function of order r and value of q - $a_r(q)$ (or $b_r(q)$), the dependency may be illustrated as follows
(from aforementioned toolbox).
You can read the following documents about Mathieu functions:
If you are interested - the toolbox installation procedure is as follows:
atomsSystemUpdateatomsInstall('Mathieu')