Is it possible to find the maximal determinant of matrices in $\{0,1\}^{n \times n}$?
If so, what do matrices with maximal determinant look like?
For example, when $n=3$, it's not hard to see that the maximal determinant is $2$, as there are only $6$ terms involved and one can brute-force it. In particular, one of such matrices is the following
\begin{pmatrix}0&1&1\\1&0&1\\1&1&0\end{pmatrix}
However, I have no idea how to generalize this argument to higher dimension.