Meaning of divergence in an integral

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What does the statement

"$\int (1/x) dx$ is logarithmically divergent when $x\to\infty$" mean?

Shouldn't integrand just be approaching zero?

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$$\int \frac{1}{x}\ dx = \ln(x)+ C$$

Which diverges as a logarithm (which indeed is) as $x\to +\infty$.