What does the statement
"$\int (1/x) dx$ is logarithmically divergent when $x\to\infty$" mean?
Shouldn't integrand just be approaching zero?
What does the statement
"$\int (1/x) dx$ is logarithmically divergent when $x\to\infty$" mean?
Shouldn't integrand just be approaching zero?
Copyright © 2021 JogjaFile Inc.
$$\int \frac{1}{x}\ dx = \ln(x)+ C$$
Which diverges as a logarithm (which indeed is) as $x\to +\infty$.