Segment of Example from Textbook:
$t=\dots$
More usefully, we have:
$t\sim n\log n$
I recall $\sim$ means "similarity" in geometry, same shape but not same size. How is it interpreted here?
Segment of Example from Textbook:
$t=\dots$
More usefully, we have:
$t\sim n\log n$
I recall $\sim$ means "similarity" in geometry, same shape but not same size. How is it interpreted here?
On
The answer by Daniel Littlewood is absolutely correct in this context. To extend this to the general definition (not tied to the example at hand):
$$f(n) \sim g(n) \iff \lim_{n\to\infty} \left(\frac{f}{g}\right)(n) = 1$$
On
The symbol $\sim$ does not have a set meaning across all subjects, but it is almost always used to denote an equivalence relation: a relation that is reflexive, symmetric, and transitive.
Daniel Littlewood and anorton have already discussed what $\sim$ means in this instance, and we can verify that it is an equivalent relation between functions on $\Bbb R$.
Clearly for any function $f(n)$, we have that $f\sim f$ since $(f/f)(n)=1$ for all $n$ (with caveats about the zeros of $f$) and $\lim_{n\rightarrow\infty}1=1$.
Also if $f\sim g$ we then have that $g\sim f$. This follows from the fact that if $\lim_{n\rightarrow\infty}h(n)=1$ then $\lim_{n\rightarrow\infty}(1/h)(n)=1$. Applying this fact with $h=f/g$ we tell us that $\sim$ is symmetric.
Finally $\sim$ is transitive. This follows from the fact that if $\lim_{n\rightarrow\infty}h_1(n)=1$ and $\lim_{n\rightarrow\infty}h_2(n)=1$ then $\lim_{n\rightarrow\infty}(h_1h_2)(n)=1$. If we have that $f\sim g$ and $g\sim h$, apply the previous fact with $h_1=f/g$ and $h_2=g/h$, and you will get that $f\sim h$.
In this context, it means that $$\lim_{n \to \infty}\frac{t}{n\log n}=1$$ That is, the quotient of both sides tends to $1$.