Metric on a finite set

586 Views Asked by At

If $X$ is a finite set and d is an arbitrary metric. Prove that $(X, d)$ is complete.

My solution:

Let $X =$ {$x_1, x_2, ... , x_n|n \in \mathbb{N}$}

$\exists N\in \mathbb{N}$ s.t. $x_n = x$ for some $x\in X$

$\therefore$ {$x_n$}$^\infty _{n = 1}\rightarrow x$

$\implies d(x_n, x)\leq \epsilon$, $\forall n>N$

$\therefore$ $x_n\rightarrow x$ as $n \rightarrow \infty$

Shows every cauchy sequence in X converges in X therefore it is complete. Not sure if this is entirely correct.

Also how do I show any two metrics on X are equivalent? What are the possible metrics on X?

1

There are 1 best solutions below

1
On

its a finite metric space, therfore there's a minimum over $d(x,y)$ where $x \ne y$ so use the fact that in a cauchy series you can get the elements of the series close as you want, and show that every cauchy series is constant from some place N, and then obviously converges to that constant.