Minimal value of $\mathbb{E}[(X-g(Y))^2]$.

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In a test I have two true/false question and I'm not sure if I got it properly:

Given X and Y as two random variable (we don't know if indipendent), with $g:\mathbb{R}\to\mathbb{R}$:

  1. $g(Y)=\mathbb{E}[X|Y]$ makes $\mathbb{E}[(X-g(Y))^2]$ minimal
  2. $c=var[X]$ makes $\mathbb{E}[(X-c)^2]$ minimal

Now, in both cases the second part resemble the formula of the variance, but I don't think I need it.

Due to the fact that both $\mathbb{E}[(X-g(Y))^2]$ and $\mathbb{E}[(X-c)^2]$ are the expected value of a square, the minimal value that they can get is zero, and they get it when $g(Y)=X$ and $c=X$.

So both the the answers should be false, but I'm not really sure if I'm missing something, can you confirm that my logic is right?

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The key point here is that when trying to define an estimator function such as $g(\cdot )$, we should note it to be deterministic rather than stochastic. The substitution $g(X)=X$ may sound reasonably good, but impractical due to it uselessness because we don't know the exact amount of $X$. Instead, we can exploit additional information, say $Y$, to make a best possible (from the aspect of minimum error variance) estimation of $X$. The more $Y$ is dependent to $X$, the better the estimator is .