Modified equation in Taylor series expansion

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Take any x ∈ R, u ∈ R, h > 0 and write the Taylor expansion

$$p(x + uh) = p(x) + p'(x)uh + · · · + \frac{(uh)^l}{(l-1)!} \int_0^1 (1-\tau)^{l-1}p^{l}(x+\tau uh) d\tau$$

$p^{l}(x)$ is nth derivative of $p(x)$

I don't understand the last term $\frac{(uh)^l}{(l-1)!} \int_0^1 (1-\tau)^{l-1}p^{l}(x+\tau uh) d\tau$ in the Taylor expansion formula

I think that's a little different from lagrange remainder

please tell me explanation in detail