Let $t>0$. Since $1-\cos x\ge0$ we have for any $k\in\mathbb{N}$ we have
$$
\int_{k\pi}^{(k+1)\pi}\exp(t\,x)\frac{1-\cos x}{x^2}\,dx\ge\frac{e^{k\pi t}}{(k+1)^2\pi^2}\int_{k\pi}^{(k+1)\pi}(1-\cos x)\,dx=\frac{e^{k\pi t}}{(k+1)^2\pi}
$$
and
$$
\sum_{k=1}^\infty\frac{e^{k\pi t}}{(k+1)^2}=+\infty.
$$
Let $t>0$. Since $1-\cos x\ge0$ we have for any $k\in\mathbb{N}$ we have $$ \int_{k\pi}^{(k+1)\pi}\exp(t\,x)\frac{1-\cos x}{x^2}\,dx\ge\frac{e^{k\pi t}}{(k+1)^2\pi^2}\int_{k\pi}^{(k+1)\pi}(1-\cos x)\,dx=\frac{e^{k\pi t}}{(k+1)^2\pi} $$ and $$ \sum_{k=1}^\infty\frac{e^{k\pi t}}{(k+1)^2}=+\infty. $$