Natural logarithm equation, beginner stage

Question

I am learning about natural logarithms and this is the first equation i must solve:

$$ 30 - 23 e^{-0.027x} > 20 $$

Could somebody explain what i should do to solve this and other equations like these? Thanks

Answer 1

Hint:

Move the constant to right:

$$-23e^{-0.027x}>-10$$

Divide with $-23$:

$$e^{-0.027x}<\frac{10}{23}$$

And now! You can soon get the log of both sides!

$$\log{e^{-0.027x}}<\log{\frac{10}{23}}$$

Good luck! And learn at least basic equation solving, without them all of such problems will be much harder!