from the book of engineering mathematics by G.Zill, I read That
"The inverse Laplace transform of a function F(s) may not be unique; in other words, it is possible that Laplace transform of f1 and f2 is same and yet f1 and f2 is different. For our purposes this is not any- thing to be concerned about."
I found if f1 and f2 is different at countable many points, he is right because of Riemann integral's property.
- however, I still wonder if there are any other case. if there are, how can we know that? (And I think this question is related to the question of the necessary condition of Lapace transform.)
- And if so, why does the inverse Laplace transform have Linearity even though their output is differ case by case?
Given that the (one-sided) Laplace transform is defined by $$ F(s) := \int_0^\infty f(t)\,e^{-st} \,\mathrm{d}t, $$ it doesn't take into account the points on the negative part of the real axis, since they lie outside the domain of integration. In consequence, functions can differ on $(-\infty,0)$ and have the same Laplace transform at the same time.
A simple example is the constant function $f(t) = 1$ in comparison with the Heaviside function $\theta(t) = 1_{(0,\infty)}(t)$, which differ at an uncoutably infinite number of points while having the same transform (namely $1/s$).
As for the linearity of the Laplace transform (and its inverse), it stems simply from the linearity of the integral towards its integrand.