Need help in discerning whether or not this is a joke question or not?

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Just a few moments ago, I have asked a question regarding a proof that my math teacher asked me to solve. But it turned out to be a joke; he was asking me to solve the ABC conjecture, which apparently is a known open question in the math community. Now I have another extra credit proof(my teacher gave 5 of them; hopefully they aren't all just jokes), but I'm having trouble figuring out if this is just another joke question or not. It is as follows:

Consider a sequence $(a_n)$ that has an initial value of $a_0=k$, where $k$ is a positive integer. Every term after that is then defined recursively as follows:$$a_n=\begin{cases}\frac{a_{n-1}}2&\text{if }a_{n-1}\equiv0\pmod2\\3a_{n-1}+1&\text{if }a_{n-1}\equiv1\pmod2\end{cases}$$Prove or disprove the statement that there are infinitely many values for $k$ such that $(a_n)$ will reach $1$ at some point.

My initial thought was to try out small values for $k$. I first tested $k=3$, which produces the following sequence:$$3,10,5,16,8,4,2,1$$ I noticed that if the sequence reaches any power of $2$, then it will eventually reach $1$. But after this, I don't know what I can do. I suppose I can try to find an explicit formula for this recursive sequence but I feel like that would be a hard task.

This problem is pretty easy to understand, yet the proof still eludes me. I didn't spend too much time on this, thinking it might be another joke, but I'm not sure if that's the case here. Any thoughts?

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People aren't reading the question carefully. This is NOT the Collatz conjecture, but a different problem about the Collatz sequence. The question given is easy to solve: Consider the infinite set $\{ 2^n | n = 1, 2, 3, \ldots\}.$