This is an electrical question but i stuck in two equations that i am unable to solve it further that need mathematics. so i am asking here, basically the two equation are these
$\displaystyle\frac{150(1-w^{2}LC)+150w^{2}LC}{(1-w^{2}LC)^{2}+(150wC)^{2}}=200$
$\displaystyle\frac{wL(1-w^{2}LC)-22500wC}{(1-w^{2}LC)^{2}+(150wC)^{2}}=300$
where $w=2\pi f$ and $f=685 kHz$
Is there any way i can get the value of L and C?
It is better to take $$x=w^2LC\\y=150wC \\\to \\\frac{x}{y}=\frac{wL}{150}$$so $$\displaystyle\frac{150(1-x)+150x}{(1-x)^{2}+(y)^{2}}=200\\ \displaystyle\frac{wL(1-x)-150y}{(1-x)^{2}+(y)^{2}}=300 \to \\\begin{cases}\displaystyle\frac{150(1-x)+150x}{(1-x)^{2}+(y)^{2}}=200\\\displaystyle\frac{\frac{x}{y}(1-x)-150y}{(1-x)^{2}+(y)^{2}}=300\end{cases} $$ then find x,y with graphing ,then find $L,C$ I graph it ,follow the below link https://www.desmos.com/calculator/o9zyhiveqn