I've tried everything. I expressed $x$ and I got $x=\ln{1\over x}$, and don't know what to do. Original question is to find $e^x-{1\over x}=0$. There is a solution I've typed it in Wolfram
2026-04-30 07:45:31.1777535131
On
Need help with $e^x=1/x$
160 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
There are 2 best solutions below
0
On
This can be rewritten as
$$ xe^x = 1$$
And here, there is no "simple" answer, you need to introduce the Lambert W function.
There is no closed solution. However note that:
$$e^x = \frac{1}{x}$$
has one real root. To see this you can consider it as a function , differentiate , determine the range etc. Therefore we have a root.
This root is a famous constant denoted as $\Omega$. Its approximate value is $0.5671$.
Otherwise, this root can be expressed via Lambert W.That is if $r$ denotes the root then we have $r=W(1)$.
P.S There exists an integral represantation of $\Omega$.