Can anyone prove / disprove$\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{...\sqrt{\sqrt{\sqrt{n}}}}}}}}} = 1$ for all $n>0$?
$\infty \sqrt{ }s $
Note: This is my first question here. Any constructive feedback is welcomed. If you are wondering, this is not a piece of homework, but a problem I encountered when trying to solve a problem in Puzzling.SE. Thanks in advance!
I assume that by such an expression with "infinitely many radicals" you really mean the limit as the number of radicals goes to infinity. (But, you really really shouldn't use notation like this without being precise about what it means.)
Given that, the answer is indeed $1$ for any $n>0$. If you iterate taking the square roots $m$ times starting from $n$, that gives you $n^{1/2^m}$. As $m\to\infty$, the exponent converges to $0$, and so since the function $x\mapsto n^x$ is continuous, $n^{1/2^m}$ converges to $n^0=1$.