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2026-03-26 12:36:57.1774528617
Newton's Laws of Motion - Question on Attwood's Machine
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First, consider the movement from A to B:
Newton's second law gives $$mg = (2M+m)a$$where $a$ is the acceleration from A to B. So we get $$a=\frac{mg}{2M+m}.$$ Besides, $v=at_{AB}$ and $h=\frac{1}{2}at_{AB}^2$ gives $v=\sqrt{2ah}$, where $v$ is the speed at B.
Secondly, consider the movement from B to C: $$vt=h$$ Put in $v=\sqrt{2ah}$, after some simple algebra, you can get $$g=\frac{h(2M+m)}{2mt^2}$$