It is well known that if $n>0$, then https://en.wikipedia.org/wiki/Binomial_coefficient
\begin{align}\binom{-n}{k} &= \frac{-n\cdot-(n+1)\dots-(n+k-2)\cdot-(n+k-1)}{k!}\\ &=(-1)^k\;\frac{n\cdot(n+1)\cdot(n+2)\cdots (n + k - 1)}{k!}\\ &=(-1)^k\binom{n + k - 1}{k}\\ &=(-1)^k\left(\!\!\binom{n}{k}\!\!\right)\;.\end{align}
Here are some questions:
the above equations holds only for $n>0$, right? If $n<0$, we should adjust accorindlgy, but this does not seem to be clearly stated in https://en.wikipedia.org/wiki/Binomial_coefficient
Frank W. J. Olver, Daniel W. Lozier, Ronald F. Boisvert, and Charles W. Clark. The NIST Handbook of Mathematical Functions. Cambridge Univ. Press, 2010. NIST it states in section 1.2 that
\begin{align}\binom{n}{k}&= (-1)^k\;\frac{(0-n) \cdot (1-n) \cdot (2-n) \dots (k-2-n)\cdot (k-1-n)}{k!}\\ &= (-1)^k\;\frac{(-n)_k}{k!}\\ &=(-1)^k\binom{ k -n - 1}{k}\end{align}
what does the symbol $(-n)_k$ mean? Is this a standard terminology? I was not able to find its meaning or interpretation in the above NIST guide.
- do we need to take care for the cases $n=0$ and $k \neq 0$, or $n\neq 0$ and $k =0$, or $n=0$ and $k=0$?
$$ 4=\binom{-(-4)}3=\frac{4\times 3\times 2}{3!}=(-1)^3\frac{(-2)\times (-3)\times (-4)}{3!}=(-1)^3\binom{-4+3-1}{3}=4 $$
$(n)_k:=\prod_{i=0}^{k-1} (n+i)$ is the rising factorial.
Everything works whether or not $n=0$ or $k=0$. There is no division by zero, because $0!=1$.