I need help with the following riccati equation
$$\ y' = Ay^2 + By + C $$
in the situation where discriminant < 0
It must be solved analytically with steps.
Thanks
I need help with the following riccati equation
$$\ y' = Ay^2 + By + C $$
in the situation where discriminant < 0
It must be solved analytically with steps.
Thanks
Copyright © 2021 JogjaFile Inc.
HINT:
$$y'(x)=ay(x)^2+by(x)+c\Longleftrightarrow$$ $$\frac{\text{d}y(x)}{\text{d}x}=ay(x)^2+by(x)+c\Longleftrightarrow$$ $$\frac{\frac{\text{d}y(x)}{\text{d}x}}{ay(x)^2+by(x)+c}=1\Longleftrightarrow$$ $$\int\frac{\frac{\text{d}y(x)}{\text{d}x}}{ay(x)^2+by(x)+c}\space\text{d}x=\int 1\space\text{d}x\Longleftrightarrow$$ $$\frac{2\arctan\left(\frac{2ay(x)+b}{\sqrt{4ac-b^2}}\right)}{\sqrt{4ac-b^2}}=x+k$$
With $k$ is an arbitrary constant