Is it true that for every measurable cardinal $\kappa$ there is a normal, $\kappa$-complete, and non-principal ultrafilter on $\kappa$ ?
2026-03-30 14:09:31.1774879771
Normal $\kappa$-complete non-principal ultrafilter on measurable cardinal $\kappa$
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Yes. This can be shown in a more purely combinatorial way, but it's probably best to follow the proofs of
This is all in Jech (as is a proof not using the elementary embedding characterization).