For addition, there is $\sum$
For multiplication, there is $\prod$
What about for division?
Something like ${/}_{i=1}^n a_i = a_1 \div a_2\ \div\ ...\ \div\ a_n$?
For addition, there is $\sum$
For multiplication, there is $\prod$
What about for division?
Something like ${/}_{i=1}^n a_i = a_1 \div a_2\ \div\ ...\ \div\ a_n$?
On
There can be a justification for a repeated subtraction, provided it is defined with right to left associativity.
Because $a_0-(a_1-(a_2-(a_3-a_4)))=a_0-a_1+a_2-a_3+a_4$ is an alternating series, which is a very frequent pattern, whereas $(((a_0-a_1)-a_2)-a_3)-a_4=a_0-a_1-a_1-a_2-a_2$ is a mere summation in disguise, and we don't need a specific notation for this very rare case.
The case of repeated division is clearer:
$$\frac{a_0}{a_1\cdot a_2\cdot a_3\cdot a_4\cdots}$$ is well replaced by a product and
$$\frac{a_0\cdot a_2\cdot a_4\cdots}{a_1\cdot a_3\cdots}$$ is of very limited use because products with the same factor expressions at the numerator and denominator are exceptional.
By natural selection, these operators have died out.
I don't believe there is such a symbol, and you can likely get what you want pretty simply with $\prod$ alone.
For instance, if $N=4$, you probably intended one of:
$$a_1/a_2/a_3/a_4=\dfrac{a_1}{ {\displaystyle\prod_{i=2}^{4}} a_i}$$
or $$a_1/(a_2/(a_3/a_4))=\dfrac{{\displaystyle\prod_{i=1}^2a_{2i-1}}}{{\displaystyle\prod_{i=1}^2a_{2i}}}\text{.}$$