How do you find $f(x)$ if you know that: $$f(2x) = 2f(x) - f(x)^2$$
The result is: $f(x)=1-e^{cx}$ (where $c$ is an arbitrary constant).
What would be the steps to get to the result?
How do you find $f(x)$ if you know that: $$f(2x) = 2f(x) - f(x)^2$$
The result is: $f(x)=1-e^{cx}$ (where $c$ is an arbitrary constant).
What would be the steps to get to the result?
Hint
With $g(x)=1-f (x) $ you obtain: $$g (2x) =g (x)^2$$ You can then look at this