I would like to ask a question about an exterior conformal mapping. Could you please help me?
Let $L$ be a Jordan curve in $\mathbb{C}.$ Let $G$ be the exterior of $L.$ Then, there exists a conformal mapping $\Phi:G\rightarrow \overline{\mathbb{C}}\setminus \{z:|z|\leq 1\}$ such that $\Phi(\infty)=\infty$ and $\Phi'(\infty)>0.$ My question is
"Is the $n$-th derivative $\Phi^{(n)}(z)\not=0$ for all $z\in G$?"
Thank you so much.
Mike
Take $L$ the unit circle and $\Phi$ the identity.Obviously $\Phi'' = 0$