Can you prove that there are exactly $90$ elements in the set of numbers having $4$ digits which are palindromes?
This is not a tricky question. I am just trying to understand the concept of proofs better.
Can you prove that there are exactly $90$ elements in the set of numbers having $4$ digits which are palindromes?
This is not a tricky question. I am just trying to understand the concept of proofs better.
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Hint: a four-digit palindrome must look like $ABBA$ where $A$ and $B$ are digits, and $A$ is nonzero. The number of ways can you choose $A$ and $B$ is the number of four-digit palindromes.