How can I find the number of digits and the last digit of the number $$\large{2357^{2357^{.^{.^{.^{2357}}}}}}$$ Basically $2357$ to the power of $2357, 2357$ times.
2026-04-12 21:48:37.1776030517
Number of digits and last digit of a number
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You won't be able to write the number of digits down, because it is larger than the number of particles in the universe.
However, the last two digits are '57'. You can see that $2357=1 \pmod{4}$, and so the whole exponent reduces to $1 \pmod{4}$. Since the period of $100$ is four places, it simply amounts to finding what $57^1$ ends in decimal - ie '57'.