Let a be the number of real numbers between 0 and 1
Let b be the number of all integers.
Can I say b=2a+1, since for every real number n where 0<n<1, I can take n and remove the 0. in the beginning, making it an integer, and have a positive and negative of that integer? I will also have 0 in the integer set which cannot be reached through above method, hence the +1.
I think the logic is pretty sound, are there any mistakes in this argument?