I have to prove that an open subset of a regular Surface is also a regular Surface I have no clue on How to start that demonstration or what Path to follow
2026-03-26 17:30:37.1774546237
Open subset of a regular surface
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Just use the fact that if you have an atlas $\mathcal{U}$ on your original surface, say $S$, then $\mathcal U':=\lbrace V\cap U \: : \: V\in\mathcal U \rbrace $ is an atlas on the open subset $U\subseteq S$.