Opposite of 'If X,Y are independent, Mx+y(t)=Mx(t)My(t)'

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It is known that If X,Y are independent random variables, Mx+y(t)=Mx(t)My(t)

It's because if X and Y are independent, f(X) and g(Y) are also independent.

How about the opposite?

It X and Y have moment generating function and Mx+y(t) = Mx(t)My(t), then X and Y are independent