$$x y^{(4)} + 2 y'' + (x y')^5 = x^3$$
Could someone please explain how this is a fourth order equation? I would have thought it was a second order equation. Does the $4^{th}$ power on the $y$ make a difference?
2026-05-04 17:01:55.1777914115
Order of this differential equation and why?
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$y^{(4)}$ is equal to the $4^{\text{th}}$ derivative of $y$.
So, the order of this equation is $4$.