I read that for the Lorentz metric defined as
$d(a,b,c,d)=-a^2+b^2+c^2+d^2$
in $R^4$ the parallel translation (corresponding to the Levi-Civita Connection of $d$) agrees with the parallel translation of $\mathbb{R}^{n+1}$.
Could someone explain why?
I read that for the Lorentz metric defined as
$d(a,b,c,d)=-a^2+b^2+c^2+d^2$
in $R^4$ the parallel translation (corresponding to the Levi-Civita Connection of $d$) agrees with the parallel translation of $\mathbb{R}^{n+1}$.
Could someone explain why?
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In $\mathbb{R}^4$, not in $\mathbb{R}^{n+1}$.
The reason is that this Lorentzian-metrics is flat : there is no curvature.