I want to calculate the parametric equations of the surface of a tape helically wound around a helix. The axis of the tape is basically a slinky https://mathworld.wolfram.com/Slinky.html.
I tried different methodologies (I started with tangent, normal and binormal vectors) without success; what I got is here Fig1 .
The surface I want to paramterize is the following one (the blue one): Fig 3
I appreciate any help you can provide. Thanks!
Update.
Using this equation:
=(+cos())cos(+) =(+cos())sin(+) =ℎ(+)+sin()
This is what I got: Fig 2


Starting from a parametrization of a 1D slinky $$ \begin{aligned}&x=(R+a\cos(\omega t))\cos(t)\\ &y=(R+a\cos(\omega t))\sin(t)\\ &x=ht+a\sin(\omega t) \end{aligned}$$ you can modify it to get a parametrization of your curve in the variables $(s,t)$: $$ \begin{aligned}&x=(R+a\cos(\omega t))\cos(t+s)\\ &y=(R+a\cos(\omega t))\sin(t+s)\\ &x=h(t+s)+a\sin(\omega t) \end{aligned},$$ where $t$ ranges in some interval $I$ (it could be $\mathbb R$) and $s\in(\varepsilon/2,\epsilon/2)$, where $\varepsilon$ is roughly the width of the band.
Edit: this one is probably closer to what you want, as it morally makes the width of the tape independent on the distance from the main symmetry axis:
$$ \begin{aligned}&x=(R+a\cos(\omega t))\cos\left(t+\frac{s}{R+a\cos(\omega t)}\right)\\ &y=(R+a\cos(\omega t))\sin\left(t+\frac{s}{R+a\cos(\omega t)}\right)\\ &x=h\left(t+ \frac{s}{R+a\cos(\omega t)}\right)+a\sin(\omega t) \end{aligned}.$$