I've been posed with the following question:
$\int^3_1(x^2\div (2x+1)) dx$
I was able to determine via long division that:
$x^2\div (2x+1)$ = $\frac12x-(\frac12x\div(2x+1))$
however, I can't determine how to get past this point, could anyone help? Working would be appreciated.
Sorry for the bad formatting, I can't figure out how to use the fraction function properly.
Long division should have given you: $$\frac{x^2}{2x+1}=\frac x2-\frac14+\frac1{4(2x+1)}.$$