If $\phi_t:A\rightarrow B$ is completely bounded for $t\in[0,1]$, and $t\mapsto\phi_t(a)$ is continuous for each $a\in A$, is $\sup_{t\in[0,1]}||\phi_t||_{cb}$ finite? Here, $A$ and $B$ are operator spaces or operator algebras.
In the setting of Banach spaces and bounded maps, it seems like the uniform boundedness principle gives a positive answer (or does it?).