PDE with 3 variables, solved. Am I right?

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I solved an exercise and I need to confront some other point of view. Given this equation

$$u_x + u_y + u_z=0$$

I solved by using characteristics, obtaining

$$\frac{dx}{1}=\frac{dy}{1}=\frac{dz}{1}$$

i.e. the system

$$ \begin{cases} dx=dy\\ dy=dz \end{cases} $$

$$ \begin{cases} x=y+K_1\\ y=z+K_2 \end{cases} $$

$$ \begin{cases} K_1=x-y\\ K_2=y-z \end{cases} $$

concluding as

$$ u(x,y,z)=\Phi(K_1+K_2)=\Phi(\Phi_1(x-y)+\Phi_2(y-z)) $$

with $\Phi, \Phi_1, \Phi_2: \mathbb{R}^3\rightarrow\mathbb{R} $

In order to prove the solutions, I substituted them in the equality.

I computed the partial derivatives

$$u_x =\frac{\partial u}{\partial x}=\Phi'(\Phi_1(x-y)+\Phi_2(y-z))\cdot(\Phi'_1(x-y))$$

$$u_y =\frac{\partial u}{\partial y}=\Phi'(\Phi_1(x-y)+\Phi_2(y-z))\cdot(-\Phi'_1(x-y)+\Phi'_2(y-z))$$

$$u_z =\frac{\partial u}{\partial z}=\Phi'(\Phi_1(x-y)+\Phi_2(y-z))\cdot(-\Phi'_2(y-z))$$

Computing the summations, result is zero, so the solutions seem correct.

Was I right in applying the method? Are the computations reported correct? Is there some theoretical passages I missed? Thanks.