Peano axioms proof

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Given that $K$ is an ordered field satisfying the least upper bound property and $1$ as the multiplicative identity, the set of natural numbers $\mathbb{N}_K$ in $K$ is defined as: $1 \in \mathbb{N}_K$ and $N + 1 \in \mathbb{N}_K$ if $N \in \mathbb{N}_K$. In this case, $N = 1 + ... + 1 \}$ $N$ times. Show that $\mathbb{N}_K$ satisfies the Peano axioms.

I am new to analysis and was not really taught about the Peano axioms and can't seem to find anything on the web about exactly what I need to prove in this problem. Can someone please briefly list and/or describe the axioms that need to be shown in order to complete the above proof? Any assistance is much appreciated.

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Suppose you are allowed to sum numbers, and if you are in the natural numbers, this is quite natural. And define the operation $S(x) = x+1$ to be it, then we have to believe:

  1. $S(x) = S(y) $, meaning that our $x$ equals $y$, so $S$ is injective;

  2. 1 is the only element, that doesn't succed any other, then there is no $x$ in natural numbers such that $S(x) = 1$;

  3. Suppose there is a subset of natural numbers with 1 inside it, then if in this subset there is another, then it's because $S(x) \in X$, and so, this subset is the natural numbers set.