To pass an examination, 40% marks are essential. A obtain 10% marks less than the pass marks and B obtains 11.11% marks less than A. What percent less than the sum of a's and b's marks should c obtain to pass the exam? (a)40% (b)41(3/17)% (c)28% (d)Any of these
Let total marks be =100
A's marks=36
B's marks=24
A+B=60
Total $=100$
$A=(100*40\%)*90\%=36$
$B=36*(100-11.11)\%=36*8/9=32$
$A+B=68$
AtMost 28 marks can be lost
$\frac{28}{68}*100\%=\frac{700}{17}\%=41\frac3{17}\%$