Trying to help a student with this, but I cannot see how I am doing it wrong. Here is the problem and the answer from the book.
Q. Tina invested $30,000$ in a stock. In the first year, the stock increased in value by $10\%$. In the second year, the stock decreased in value by $20\%$. What percent- age gain is required in the third year for Tina’s stock to return to its original value? (Round to the nearest tenth of a percent.)
A. $13.6\%$
My work: The first year as $30000*10\%=3000$, $30000+3000=33000$
Second year as $33000*-20\%=-6600$, $33000-6600=26400$
Third year as $26400/30000=0.88,$ $1-0.88=.12=12\%$
By steps, please, what am I doing wrong?
Your steps were fine until you calculated the third-year percentage. It looks like you calculated the percentage growth relative to the original amount ($\$30,000$) rather than relative to the amount after the second year ($\$26,400$).
You can think of this like an algebraic equation:
$$\begin{align*} 26 \ 400 \times \left(1 + \frac{x}{100} \right) &= 30 \ 000\\[5pt] 1 + \frac{x}{100} &= \frac{30 \ 000}{26 \ 400}\\[5pt] \frac{x}{100} &= \frac{3 \ 600}{26 \ 400} \\[5pt] x &= \frac{3 \ 600}{264} \approx 13.6 \\[5pt] \end{align*}$$
In short, the amount Tina needs to make up - $\$3,600$ - is $12\%$ of $\$30,000$ as you have calculated, but that is not the value the question is looking for. The question is looking for the amount that Tina needs to gain based on what she has after the second year. $\$3,600$ is $13.6\%$ of $\$26,400$, which is why it is the answer.