Permutation cycles

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My tasks are the following :

Task 1 :

Prove that $ \begin{pmatrix} 1 & 2 & \cdots & r-1 & r \end{pmatrix} = \begin{pmatrix} 2 & 3& \cdots & r & 1 \end{pmatrix} = \begin{pmatrix} 3 & 4 & \cdots & 1 & 2 \end{pmatrix}= \cdots = \begin{pmatrix} r & 1 &\cdots & r-1 \end{pmatrix}$

and conclude that there are exactly r such notations for a r-cycle

My Attempt:

My understand of why this would be true as follows:

You are given a permutation $f \in S_X $ such that:

$f(1) =2 , f(2) =3 ,\ldots , f(r-1) = r , f(r) =1$

So when constructing a r-cycle, we r choices for the first element in the cycle, while the remaining $r -1 $ elements are dictated by $f$ and hence:

$r \times 1 \times 1 \times \cdots \times 1 = r $.

Task 2:

if $1 \leq r \leq n $ then there are $ \frac 1r [ n(n-1)\ldots (n-r +1)]$ r-cycles in $S_n$

My Attempt:

I again have some understanding of why this is true. You have a set of $n$ elements. Of which you want to find all possible r-cycles , this is the number of permutations of the n elements taken r element at a time divide by r i.e. the number of way a cycle can be represented

Can you offer any suggestions or tips on how to convert these rough ideas in fully fetched rigorous proofs?

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You are almost done. Just put this into mathematical grammar (i.e. use the definition of a cycle by $(a_0, f(a_0), \ldots, f^r(a_0))$ and remark that $a_0$ is in a set of cardinality $r$ (namely the elements of the cycle of length $r$).
For Task 2, the argument is already formulated well. Just say that you are using the result from Task 1.