I have been asked to simplify the following expression in an assignment problem:
X’YZ + XYZ + XY’Z’+XYZ’ + XY’Z’ + X’Y’Z’ + WX’Y’Z’ + W’X’Y’Z’
The result of the simplification should only be 2 terms. I have attempted many times and I have been only arriving at three terms at best. Below are my steps:
(X’ + X) YZ + (Y’+Y) XZ’ + (X + X’) Y’Z’ + (W + W’) X’Y’Z’
YZ + XZ’ + Y’Z’ + X’Y’Z’
YZ + (X + Y’) Z’ + X’Y’Z’
YZ + (X + Y’ + X’Y’) Z’
YZ + (X + Y’ (1 + X’)) Z’
YZ + (X + Y’) Z’
YZ + XZ’ + Y’Z’
I am not sure how to go 2 terms from here. Any help would be much appreciated.
Thanks in advance!