Need help here on dealing with the fractions. I need to find the point of intersection using substitute method. \begin{align} y&= \frac{1}{2}x - 2\\ y&= \frac{3}{4}x + 3\\ \end{align} Initial step of solution: \begin{align} \frac{1}{2}x-2 &= \frac{3}{4}x+3 \end{align}
What must I do next to find the X int?
Just edited, sorry. Should be good now thanks.
If my edits are correct, then you next need to apply the idea that if two things are equal, such as $$ C = D $$ and $r$ is any number, then $$ rC = rD $$.
In your case, part of the problem is that there are fractions; the largest denominator is 4. If you pick $r = 4$ and apply the idea above, you get
\begin{align} \frac{1}{2}x-2 &= \frac{3}{4}x-3\\ 4 \left[ \frac{1}{2}x-2\right] &= 4 \left[\frac{3}{4}x-3 \right] \\ \frac{4}{2}x-4 \cdot 2 &= \frac{4 \cdot 3}{4}x-4 \cdot 3 \\ 2x-8 &= 3x-12 \end{align} and you can probably do some more algebra to find the value of $x$.