Poisson Distribution Confidence Interval

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Suppose I have 6 pieces of data from a poisson experiment:

4, 6, 8, 10, 12, and 14.

$\hatλ$ = 9. I want to establish a 95% confidence interval for this poisson experiment, and z* = 1.960. So I do the following:

Upper boundary:

$λ+1.960\sqrt{λ}$

$9+1.960\sqrt{9}$

$14.88$

Lower boundary:

$λ-1.960\sqrt{λ}$

$9-1.960\sqrt{9}$

$3.12$

Is this work mathematically sound?

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As for interpreting the confidence interval, I'm lost. What does the confidence interval mean?

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What you have is not a confidence interval. A confidence interval should be based on data. If you know that $X_i \sim \mathsf{Pois}(\lambda = 9),$ what is the point of getting an interval estimate of $\lambda?$

From the corrected data ($4,6,8,10,12,14$), you have $\bar X = \hat \lambda = 9.0.$

One simple style of approximate confidence interval for $\lambda$ is the so-called Wald 95% CI. It is of the form

$$\bar X \pm 1.96\sqrt{\bar X/n}.$$

This would be an approximate confidence interval based on data, and would give a somewhat similar result: $(6.60, 11.40).$

A somewhat better style of 95% CI for the Poisson mean $\lambda$ uses $T = n\bar X$ to get a CI for $n\lambda$ as $$T + 2 \pm 1.96\sqrt{T + 1},$$ and then divide the endpoints by $n$. The resulting 95% CI is $(7.1, 11.9).$

There are many styles of Poisson confidence intervals, you should use the one given in your text. (But I don't understand what the t distribution has to do with a Poisson CI.)

Note: Per Comments, I'm showing a graph of the PDF of $\mathsf{Pois}(9)$ compared with the density curve of $\mathsf{Norm}(\mu=9,\,\sigma=3).$

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