Pole on the contour $\oint_{|z|=3} \frac{(z-1)^2}{(z-2)^2(z-3)} dz$

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How would you calculate the following closed contour integral where one of the poles is on the contour?$$\oint_{|z|=3} \frac{(z-1)^2}{(z-2)^2(z-3)} dz$$

I've only been given questions where the poles are either inside and/or outside the contour, but never on the contour.