Polylogarithm - derivative with respect to order

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Does anybody know where I could find the expression for $$\frac{\partial}{\partial s}\mathrm{Li}_s(z)\bigg|_{s=0}$$ or something similar?

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For every $|z|<1$, we have $$ \frac{\partial}{\partial s}\mathrm{Li}_s(z)\Big|_{s=0} = -\sum_{n=1}^\infty \log (n)\frac{z^n}{n^s} \Big|_{s=0} = -\sum_{n=1}^\infty \log(n)\,z^n $$

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