Positivity of semigroup $(P_t)_{t\geq0}$ implies its contractivity, $\| P_tf\| \leq \|f\|$

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Let $\Omega$ be a Polish space, denote $E = (C_b(\Omega),\|\cdot\|)$ be the Banach space of continuous and bounded functions with the usual supremum norm. A family $(P_t)_{t\geq 0} $ of linear operators on $E$ is called a semigroup iff

  1. $P_0 = I$, the identity map on $E$,
  2. The map $t\mapsto P_t$ is continuous in the sense: $\forall f \in E$, $t\mapsto P_tf$ is a continuous map from $\mathbb R^+$ to $E$,
  3. $P_{t+s} = P_tP_s, \forall t,s \geq 0$,

A semigroup is called Markov if in addition,

  1. $P_t1 = 1$, (1 is the function that takes only value 1),
  2. $P_t$ is positive, i.e, if $f\geq 0$ then $P_tf \geq 0$.

Questions:

A) Prove that if $P$ is Markov then it is contractive, i.e, $\| P_tf\| \leq \| f\| $?

B) Let $A$ be a positive bounded linear operator on $E$, and that $\| A \| \leq 1$ (in operator norm), $A1 =1$. Let $\lambda >0 $. Verify that $$ P_t := e^{t\lambda(A-I)} = \sum_{n=0}^\infty \frac{(\lambda t)^n}{ n!}(A-I)^n $$ is a Markov operator.

Context: I encountered A) in a lecture note, which I don't know how to prove and begin with. For B), I can only verify 1,3,4. I don't know how to verify the continuity (2.) and also, I suspect that it is differentiable as well. For 5., I have tried to prove the finite sum $H_N = \sum^N_{n=0}...$ has the property

$$\| H_Nf \| \leq \| f\|,$$

for $N=0,1,2,3$, but I don't know quite how to do it inductively for all $N$.

I hope to get a detailed treatment of 2. and its differentiability as well if possible (for me to learn this kind of calculus) and only some hints on A) and how to prove 5 inductively. Thank you in advance :D.