Consider the function
$f(t) = 3+t-(t-3)^2\theta(t-3)$,
where $\theta(t)$ is the heaviside step function.
Can i solve the equation $f(t) = 0$ somehow?
Consider the function
$f(t) = 3+t-(t-3)^2\theta(t-3)$,
where $\theta(t)$ is the heaviside step function.
Can i solve the equation $f(t) = 0$ somehow?
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